All categories

2 years ago

The graph of the function

1 answer:

5 0

F(x)=|x+3|-5 is the transformed function.
Take 3 values of x, -4, -3, -2 original f(x) for these are 1, 0, 1.
The same values for the transformed function are -4, -5, -4.
If we try to bring the -5 into the modulus, we get |x-2|. Now putting the values of x in we get: 6, 5, 4 and the graph is also displaced sideways so the solution is the transformed f(x)=|x+3|-5.

You might be interested in

Write the equation of the line that passes through (5.-9) and (2.5).

Kipish [7]

Answer:

y = -14/3x + 43/3

Step-by-step explanation:

y2 - y1 / x2 - x1

5 - (-9) / 2 - 5

14 / -3

- 14/3

y = -14/3x + b

5 = -14/3(2) + b

5 = -28/3 + b

43/3 = b

y = -14/3x + 43/3

4 0

2 years ago

Suppose it is known that 60% of radio listeners at a particular college are smokers. A sample of 500 students from the college i

vladimir1956 [14]

Answer:

The probability that at least 280 of these students are smokers is 0.9664.

Step-by-step explanation:

Let the random variable X be defined as the number of students at a particular college who are smokers

The random variable X follows a Binomial distribution with parameters n = 500 and p = 0.60.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1. np ≥ 10

2. n(1 - p) ≥ 10

Check the conditions as follows:

$np=500\times 0.60=300>10\\n(1-p)=500\times(1-0.60)=200>10$

Thus, a Normal approximation to binomial can be applied.

So,

$X\sim N(\mu=600, \sigma=\sqrt{120})$

Compute the probability that at least 280 of these students are smokers as follows:

Apply continuity correction:

P (X ≥ 280) = P (X > 280 + 0.50)

= P (X > 280.50)

$=P(\frac{X-\mu}{\sigma}>\frac{280-300}{\sqrt{120}}\\=P(Z>-1.83)\\=P(Z$

*Use a z-table for the probability.

Thus, the probability that at least 280 of these students are smokers is 0.9664.

8 0

2 years ago

Each container has a base of 4 1/4 yds by 1 2/3 yds. What is the area covered by all the containers?

svet-max [94.6K]

Answer:

See Explanation

Step-by-step explanation:

Given

Base Dimension

$Length = 4\frac{1}{4}yd$

$Width = 1\frac{2}{3}yd$

Required

The base area of all containers

First, calculate the base area of 1 container.

This is calculated as:

$Area = Length * Width$

$Area = 4\frac{1}{4}yd * 1\frac{2}{3}yd$

Express as improper fraction

$Area = \frac{17}{4}yd * \frac{5}{3}yd$

So, we have:

$Area = \frac{17*5}{4*3}yd^2$

$Area = \frac{85}{12}yd^2$

The number of containers is not given. So, I will use 'n' as the number of containers.

So, we have:

$Total = n * Area$

$Total= n * \frac{85}{12}yd^2$

--------------------------------------------------------------------------------------------

Assume n is 3 (i.e. 3 containers)

The total area is:

$Total= 3 * \frac{85}{12}yd^2$

$Total= \frac{85}{4}yd^2$

$Total= 21\frac{1}{4}yd^2$

--------------------------------------------------------------------------------------------

6 0

2 years ago

Jason has 5 carrots, he gives 2 to a friend. How many carrots does he have left?

MariettaO [177]

Answer:3

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Melinda earns 10 minutes to play video games for every hour she spends on homework.

Naily [24]

Answer:

30 minutes

Step-by-step explanation:

if she earns 10 minutes per hour and there are 3 hours, 10 times 3 is 30

6 0

2 years ago

Read 2 more answers