Answer:
Step-by-step explanation:
Assuming there is a punitive removal of one point for an incorrect response.
Five undiscernable choices: 20% chance of guessing correctly -- Expectation: 0.20*(1) + 0.80*(-1) = -0.60
Four undiscernable choices: 25% chance of guessing correctly -- Expectation: 0.25*(1) + 0.75*(-1) = -0.50
I'll use 0.33 as an approzimation for 1/3
Three undiscernable choices: 33% chance of guessing correctly -- Expectation: 0.33*(1) + 0.67*(-1) = -0.33 <== The approximation is a little ugly.
Two undiscernable choices: 50% chance of guessing correctly -- Expectation: 0.50*(1) + 0.50*(-1) = 0.00
And thus we see that only if you can remove three is guessing neutral. There is no time when guessing is advantageous.
One Correct Answer: 100% chance of guessing correctly -- Expectation: 1.00*(1) + 0.00*(-1) = 1.00
The answer is A. 42
Solution:
Let x= ones digit, y=tens digit
1st condition (original number) : 7(x+y)=10y + x
2nd condition (new number by reversing the digits): 18+x+y=10x+y
simplifying:
1st condition: 6x=3y
2nd condition: x=2
substituting x=2 to 6x=3y
<span>y=4</span>
Answer:
We have: g(x)=(x+2)(x-1)(x-2)
multiply the 3 terms:
- (x+2)(x-1)(x-2)
- (x²-4)(x-1)
- x^3 -x²-4x+4
This is a polynimial function with 2 vertices
The roots are approximatively:
0.8 and -1.5
their images are:
1.9 and 8.8
plot these two vertices and draw some other points
here is a drawing:
Answer: 112.5 square units
Step-by-step explanation:
I think:
For the triangle:
1/2base(height) = 1/2(9)(7)= 31.5 sq. Units
For the small rectangle:
Length x width= 3 x 9 = 27 sq. Units
For the larger rectangle:
The length must be 16 - 7 - 3 = 6
So length x width = 6 x 9 = 54 sq units
Now add them together:
31.5 + 27 + 54 = 112.5 square units
First we need to isolate the variable so we add 15 to both sides which is
w/4=43 then we need to multiply by 4 to both sides so its 4w=172
then divide by 4 which is 43 so the answer is w=43