(2x-1)(2x-1)
(4x^2+2x+1)(2x-1)
(2x-1) cancels out so
2x-1
4^2+2x+1
Answer:
10
Step-by-step explanation:
Let c = sum of ages of all children.
mean age of all children = c/15 = 7
c = 15 * 7 = 105
The sum of the ages of all children is 105.
Let b = sum of ages of the 9 boys.
mean age of boys = b/9 = 5
b = 9 * 5 = 45
The sum of the ages of the boys is 45.
The sum of the ages of the girls is c - b.
c - b = 105 - 45 = 60
The number of girls is 15 - 9 = 6
mean age of girls = (sum of ages of the girls)/(number of girls) =
= 60/6 = 10
Answer: 1770 rupees
Step-by-step explanation:
To solve this, we first calculate the simple interest which will be:
= (P × R × T) / 100
= (1500 × 9% × 2) / 100
= (1500 × 0.09 × 2) / 100
= 270
The total amount tha she'll get will be:
= 1500 + 270
= 1770 rupees
Total children = 6
1) Probability of 4 girls =4/6=0.66
Probability of at least 4 girls >_ 0.66
That is greater or equal to 0.66
2) probability of 5 girls = 5/ total children
=5/6=0.83
Probability of at most 5 girls <_ 0.83
That is less than equal to 0.83
