Answer:
Step-by-step explanation:
Using the given expressions, we can write the area as ...
A = BH
42 = (2x +1)(x +3) = 2x^2 +7x +3
2x ^2 +7x -39 = 0
(x -3)(2x +13) = 0
x = 3 or -6.5 . . . . . these values make the factors be zero
In order for the parallelogram to have positive dimensions, the value of x must be 3. So, the base and height are ...
base = 2(3) +1 = 7
height = 3 +3 = 6
Answer:
−8.85174904 The first answer
Step-by-step explanation:
For this case we have the following expression:
The terms are not similar, so they cannot be added.
<em>Examples of similar terms:</em>
Then, the expression given can only be rewritten as:
This is taking common factor 2 to both terms.
Answer:
Your question evokes several thoughts. Here are two of them:. 1). It takes 3 points not all on the same line to define a plane. 2). Two points ALWAYS lie on the same line.
Answer:
x = 150°
Step-by-step explanation:
The given parameters are;
AB ║ DC
∠BAE = 105°
∠AEC = 25°
We construct a line CF from C parallel to the line AE as presented in the included diagram created with Microsoft Visio
We have;
∠DCF ≅ ∠BAE = 105° by similar angles formed by two pairs of parallel lines
∠AEC = ∠ECF = 25° by alternate interior angles formed by two parallel lines and a common transversal
x = 125° + 25° = 150° By angle addition postulate
x = 150°.