Answer:
option B.
Explanation:
Given,
V₁ = 156 L
P₁ =2 atm
Now, in the cylinder
P₂ = ?
V₂ = 36
Using relation between pressure and volume
Hence, pressure is equal to 8.67 atm.
Hence, the correct answer is option B.
Answer:
C
Explanation:
If you add enough heat to a solid it eventually becomes a liquid
Answer:
5)0.53liters
6)1.634.6°c
Explanation:
5) v1=25liters, t1=12000°c. v2=?, t2=250°c
v2=(250×25)/12000
v2=6250/12000
v2=0.52liters
6)v1=130,v2=85, t1=2500, t2=?
t2=(85×2500)/130
t2=212500/130
t2= 1634.6°c
Germanium (Ge) is an element that has chemical behavior similar to that of silicon (Si) and lead (Pb). As it has an atomic mass greater than that of sulfur (S), but less than that of cadmium (Cd).
<h3>Why does the element of the same group have similar chemical behavior?</h3>
The chemical behavior of elements depends on the number of valence electrons in their outermost shell. Elements placed in the same group have the same number of valence electrons. Therefore, elements placed in the same group of the periodic table have similar chemical properties.
The elements having a similar outer electronic configuration in their atoms are arranged in the same group of the periodic table. These valence electrons are responsible chemical properties and reactivities of the elements.
Therefore, silicon and lead can be replaced by any element belonging to the same group in which Si and Pb are present. So we have germanium and tin. But germanium is the element that has an atomic mass greater than sulfur (S), but less than cadmium (Cd).
Learn more about elements with similar chemical behavior, here:
brainly.com/question/5364617
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Answer:
The heat of combustion for the unknown hydrocarbon is -29.87 kJ/mol
Explanation:
Heat capacity of the bomb calorimeter = C = 1.229 kJ/°C
Change in temperature of the bomb calorimeter = ΔT = 2.19°C
Heat absorbed by bomb calorimeter = Q
Moles of hydrocarbon burned in calorimeter = 0.0901 mol
Heat released on combustion = Q' = -Q = -2,692 kJ
The heat of combustion for the unknown hydrocarbon :
