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3 years ago

11

What is bulimia? can someone explain it to me.

2 answers:

Charra [1.4K]3 years ago

4 0

It is an emotional disorder involving distortion of body image and an obsessive desire to lose weight, in which bouts of extreme overeating are followed by depression and self-induced vomiting, purging, or fasting.<span>The exact cause of bulimia is currently unknown; though it is thought that multiple factors contribute to the development of this eating disorder, including genetic, environmental, psychological, and cultural influences. Some of the main causes for bulimia include:
</span><span>Stressful transitions or life changes
History of abuse or trauma
Negative body image
Poor self-esteem
<span>Professions or activities that focus on appearance/performance</span></span>

Serjik [45]3 years ago

3 0

Answer:

It is a obsessive eating disorder. Where one eats over the average amount and then makes themselves vomit. This is called purging. It is one of 3 main eating disorders. It is a very complex and misunderstood disease. One typically confuses it with binge eating or anorexia.

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2 C6H14 + 19 O2 --> 12 CO2 + 14 H2O

Rashid [163]

Answer:

4.06 mol H₂O

Explanation:

2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O

First we <em>convert the given masses of reactants into moles</em>, using <em>their respective molar masses</em>:

250 g O₂ ÷ 32 g/mol = 7.81 mol O₂

50 g C₆H₁₄ ÷ 86 g/mol = 0.58 mol C₆H₁₄

Now we <u>calculate how many O₂ moles would react completely with 0.58 C₆H₁₄ moles</u>, using the <em>stoichiometric coefficients of the reaction</em>:

0.58 mol C₆H₁₄ * $\frac{19molO_2}{2molC_6H_{14}}$ = 5.51 mol O₂

As there are more O₂ moles than required (7.81 vs 5.51), O₂ is the reactant in excess. That means that <em>C₆H₁₄ is the limiting reactant</em>.

Now we can <u>calculate how much water can be formed</u>, using <em>the number of moles of the limiting reactant</em>:

0.58 mol C₆H₁₄ * $\frac{14molH_2O}{2molC_6H_{14}}$ = 4.06 mol H₂O

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Explanation:

The expression used will be :

$M_1V_1+M_2V_2=M_3V_3$

where,

$M_1$ = concentration of first antifreeze= 60%

$M_2$ = concentration of second antifreeze= 10%

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$60\times x+10\times 8=20\times (x+8)$

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