A music store sells used cds for $5 each and buys used CDs for$1.50 each. you go to the store with $20 and some CDs to sell. you
1 answer:
Let x be the number of CDs we buy and y the number of CDs we sell.
Each CD sell for $1.5, then the total of money we earn is $1.5y.
Each CD bought for $5, then the total money spent is $-5x
Add the above values like this:
1.5y-5x
We have $20, add them like this:
1.5y-5x+20
Since we want to have<span> at least $10 left when you leave the store, then
we deduce the equation:
</span>
Each CD sell for $1.5, then the total of money we earn is $1.5y.
Each CD bought for $5, then the total money spent is $-5x
Add the above values like this:
1.5y-5x
We have $20, add them like this:
1.5y-5x+20
Since we want to have<span> at least $10 left when you leave the store, then
we deduce the equation:
</span>
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Answer:
We also know that for Wedneday we have two times tickets for adults compared to child so we have
And using this condition we have:
And solving for X we got:
So then the number of tickets sold for child are 36
Step-by-step explanation:
For this problem we can set upt the following notation
X = number of tickets for child
Y= number of tickets for adults
And we know that the total revenue for Wednesday was 831.60. So then we can set up the following equation for the total revenue
We also know that for Wedneday we have two times tickets for adults compared to child so we have
And using this condition we have:
And solving for X we got:
So then the number of tickets sold for child are 36
This is the answer
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