Quadrilateral EFGH was dilated by a factor of 3. What is FG F'G'

What to fractions equal 1/3

makkiz [27]

Answer:

2/6 and 3/ 9 just multiply by whatever on both sides

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

The graph shows the relationship.....

Anna35 [415]

Answer:

Part A: That 6 pounds of rice costs $18

Part B: (1,3) represents the unit price

Part C: 4 pounds of rice, because $12/3 equals 4

Step-by-step explanation:

Part A: The first point, 6, is on the amount of rice axis and the second point, 18, is on the total cost axis.

Part B: The unit price means the price for just 1 of something, so if you go to 1 pound of rice on the graph, you see it's at 3 on the total cost axis. Which means that 1 pound of rice costs $3.

Part C: From Part B you know that 1 pound of rice equals $3. So if you spend $12, then you can divide that by $3 to see how many pounds of rice you bought. 12/3 equals 4, so you bought 4 pounds of rice. Or you can count by 3's until you get to 12: 3, 6, 9, 12. That's 4 times so that means you bought 4 pounds of rice.

5 0

2 years ago

How do i make this fraction (7/3) a mixed number?

uranmaximum [27]

You get the whole numbers (1's) out of it and show the left over fraction next to it. (e.g. there is 7/3 as a mixed number is 2 1/3 )

7 0

2 years ago

a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-

Tresset [83]

Answer:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

$M = \frac{1}{2}(Lower + Upper)$

Where

$Lower \to$ Lower class interval

$Upper \to$ Upper class interval

So, we have:

Class 63-65:

$M = \frac{1}{2}(63 + 65) = 64$

Class 66 - 68:

$M = \frac{1}{2}(66 + 68) = 67$

When the computation is completed, the frequency distribution will be:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

$\bar x = 70.2903$