For this case we have an equation of the form:
h (t) = - (1/2) * a * t ^ 2 + vo * t + h0
Where,
vo: initial speed
a: acceleration:
h0: initial height.
We have the following equation:
h (t) = - 16t2 + 19t + 110
Therefore, the initial velocity is:
vo = 19 feet / s
Answer:
The initial velocity when the rock is thrown:
vo = 19 feet / s
Step-by-step explanation:
Where is the expression?
Answer:2-4=
Step-by-step explanation:y-16-(-42)
y-16+16
y-32
y-16-(-22)
y-16+4
y-20
y-16-(02)
y-16
y-16-(42)
y-0
