Answer:
Thomas buys a cardboard sheet that is 8 by 12 inches.
Let x be the side length of each cutout. So, from two sides, the cut out is 2x.
Part A:
The volume of the food dish is given by :
=
To find the zeros, we equate the above equation to 0
or
Taking out 4 common, we get
Solving this we get;
x=0, x=4, x=6
Part B:
Now we will differentiate the equation to get the value of x, and to obtain the maximum capacity. We will further equate that to zero. So, we get the equation as ;
Solving this we get x = 1.57 and x = 5.1
Hence, x = 1.57 will give the maximum capacity.
Part C:
Thomas wants a volume of 12 cubic inches, we will equate to 12.
=>
We get,
x = 0.1321
x = 6.217 (neglect biggest value)
x = 3.6502
Part D:
The connection between the cutout and the volume of the box can be described as: When we increase the cutout dimensions of the box, the volume increases up to the measurement of 1.57 inches. More than this the volume starts decreasing.
Part E:
The equation that would work for any cardboard sheet length, q, and width, p is ;