Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran
anastassius [24]
(x; y) -> (x - 2; y + 4)
J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)
K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)
L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)
M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)
Answer:
uhhhhhhh you have to figure out what x is then choose wether it is the other variable a dependent variable, and explanatory variable, or a response variable
Step-by-step explanation:
easy as that
The outlier is the number that’s farther away from the others, in this case it’s 9. The mean is the average of all the data points so it is 77/20 or 3.85. Finally, the range is the highest number minus the lowest number, so the range is 8.
THE ANSWER IS LOOK AND FIGURE WHERE IT GOES LIKE THIS IS EASY JUST PAY ATTENTION
Answer:
Step-by-step explanation:
x € R