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2 years ago

Quadratic equation that contain the three ordered pairs (1,6), (3,26), (-2,21)

Mathematics

1 answer:

rosijanka [135]2 years ago

8 0

Y= 3x^2-2x+5

6= 3(1)^2-2(1)+5
6= 3-2+5

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Use completing the square to solve the equation x^2+16x=-44.

Sidana [21]

Step-by-step explanation:

our equation is x²+16x = -44

x²+16x= -44
x² is the first term so weill have in the middle 2*x* a number
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the third term is 8² wich is 64 so we will add it in both sides
x²+2*x*8+64 = -44+64
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Answer :

$(x+1)^2+(y-1)^2=4^2$ and $(x+1)^2+(y-1)^2=16$

Step-by-step explanation:

Given : A circle with the same radius as the circle shown but with a center at (-1.1).

To find : Which equation represents a circle ?

Solution :

The equation of a circle with center (h,k) and radius r is given by :

$(x-h)^2+(y-k)^2=r^2$

Here, we are given (h,k)=(-1,1)

and radius r=4 units

So, equation of circle will be :

$(x-(-1))^2+(y-1)^2=4^2$

$(x+1)^2+(y-1)^2=4^2$

or $(x+1)^2+(y-1)^2=16$

Therefore, the required equations of circle are

$(x+1)^2+(y-1)^2=4^2$ and $(x+1)^2+(y-1)^2=16$

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