When acceleration is constant, the average velocity is given by
where and are the final and initial velocities, respectively. By definition, we also have that the average velocity is given by
where are the final/initial displacements, and are the final/initial times, respectively.
Take the car's starting position to be at . Then
So we have
You also could have first found the acceleration using the equation
then solve for via
but that would have involved a bit more work, and it turns out we didn't need to know the precise value of anyway.
Answer:
a
The number of fringe is z = 3 fringes
b
The ratio is
Explanation:
a
From the question we are told that
The wavelength is
The distance between the slit is
The width of the slit is
let z be the number of fringes that appear between the first diffraction-envelope minima to either side of the central maximum in a double-slit pattern is and this mathematically represented as
Substituting values
z = 3 fringes
b
From the question we are told that the order of the bright fringe is n = 3
Generally the intensity of a pattern is mathematically represented as
Where is the intensity of the central fringe
And Generally
Answer:
796.18 Hz
Explanation:
Applying,
Maximum velocity = Amplitude×Angular velocity
Therefore,
V' = A(2πf)............... Equation 1
Where V' = maximum velocity of the eardrum, A = Amplitude of vibration of the eardrum, f = frequency of the eardrum vibration, π = pie
make f the subject of the equation
f = V'/2πA................ Equation 2
From the question,
Given: V' = 3.6×10⁻³ m/s, A' = 7.2×10⁻⁷ m,
Constant: 3.14.
Substitute these values into equation 2
f = 3.6×10⁻³/( 7.2×10⁻⁷×2×3.14)
f = 796.18 Hz
<span>A 67.0 kg crate is being raised by means of a rope. Its upward acceleration is 3.50 m/s2. What is the force exerted by the rope on the crate?
</span>Newton's Second Law<span> of Motion states, “The force acting on an object is equal to the mass of that object times its acceleration.” We calculate as follows:
</span>
F = ma = 67.0 kg (3.50 m/s^2) = 234.5 J
Answer:
The answer is below!
Explanation:
Water waves are an example of waves that involve a combination of both longitudinal and transverse motions. As a wave travels through the waver, the particles travel in clockwise circles. The radius of the circles decreases as the depth into the water increases
Hope I helped!!
:)