Answer:
36x^6/y^10
Step-by-step explanation:
First evaluate the parentheses, 6x^3 x 6x^3 = 36x^6
y^5 x y^5 = y^10 ; remember m^k x m^r = m^k+r
final answer should be 36x^6/y^10
hope this helps :')
An= mth term.
an=a₁+(n-1)*d
a₁₂=41
a₁₅=140
a₁₂=41
41=a₁+(12-1)*d
41=a₁+11d
a₁+11d=41 (1)
a₁₅=140
140=a₁+(15-1)*d
140=a₁+14d
a₁+14d=140 (2)
With the equiations (1) and (2) build a system of equations
a₁+11d=41
a₁+14d=140
we solve it.
-(a₁+11d=41)
a₁+14d=140
--------------------
3d=99 ⇒d=99/3=33
a₁+11d=41
a₁+(11*33)=41
a₁+363=41
a₁=41-363=-322
an=a₁+(n-1)*d
an=-322+(n-1)*33
an=-322+33n-33
an=-355+33n
an=-355+33n
To check:
a₁₂=-355+33*12=-355+396=41
a₁₅=-355+33*15=-355+495=140.
SSS = Side-Side-Side
If three sides of one triangle are congruent to three sides of another triangle then the triangles are congruent.
SAS = Side-Angle-Side
If two sides and the included angle are equal to the corresponding parts of another triangle then the triangles are congruent.'
The angle must be formed by the two pairs of congruent, corresponding sides of the triangles. If the angles are not formed by the two sides that are congruent and corresponding to the other triangle's parts then you cannot use the SAS postulate.
you will notice that the main difference between the two postulates is that the SAS consists of an angle and the SSS does not.
hope this helps :)
Answer:
a. Point S
b. Line segment PT and Line segment ST
c. PSQRU
d. Lines PR and SQ
e. Plane C and Plane QRS
Step-by-step explanation: