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2 years ago

Find the range of data set: -5 -6 -1 -3 6 10

Mathematics

2 answers:

Alex73 [517]2 years ago

5 0

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Akimi4 [234]2 years ago

3 0

The correct answer is

Range: 16

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Emma and her family are saving for college. The first year will cost $18,500. She received a scholarship for $3,000 and her pare

nata0808 [166]

Answer:

$4,650

Step-by-step explanation:

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2 years ago

HELP ASAP PLEASE & SHOW UR WORK!! THANK YOU <333

alekssr [168]

Answer:

$\bold{x_1=-\dfrac{3+\sqrt{41}}{2}\approx-4.7\ ,\quad x_2=-\dfrac{3-\sqrt{41}}{2}\approx1.7}$

Step-by-step explanation:

$-2x^2-3x+4=0\\\\a=-2\,,\ b=-3\,,\ c=4\\\\\\x=\dfrac{-b-\sqrt{b^2\pm4ac}}{2a}=\dfrac{-(-3)\pm\sqrt{(-3)^2-4(-2)(4)}}{2(-1)}=\dfrac{3\pm\sqrt{9+32}}{-2}\\\\\\x_1=-\dfrac{3+\sqrt{41}}{2}\approx-4.7\ ,\qquad x_2=-\dfrac{3-\sqrt{41}}{2}\approx1.7$

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2 years ago

Answer for the square root(5x-9)+1=x

Evgen [1.6K]

$\bf \sqrt{5x-9}+1=x\implies \sqrt{5x-9}=x-1\implies 5x-9 = (x-1)^2 \\\\\\ 5x-9=\stackrel{\mathbb{FOIL}}{x^2-2x+1}\implies 5x=x^2-2x+10\implies 0=x^2-7x+10 \\\\\\ 0=(x-5)(x-2)\implies x= \begin{cases} 5\\ 2 \end{cases}$

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2 years ago

X2 - 6x + 12 and y = 2x - 4, algebraically are

olga_2 [115]

The solution is (4, 4)

Solution:

Given system of equations are:

$y = x^2 - 6x + 12 ------ eqn\ 1\\\\y = 2x - 4 ---------- eqn\ 2$

Substitute eqn 2 in eqn 1

$x^2 - 6x + 12 = 2x - 4$

Make the right side of equation 0

$x^2 - 6x + 12 - 2x + 4 = 0\\\\x^2 -8x + 16 = 0$

Solve by quadratic equation

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=-8,\:c=16:\\\\x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}\\\\x=\frac{-\left(-8\right)\pm \sqrt{0}}{2\cdot \:1}\\\\x = \frac{8}{2}\\\\x = 4$

Substitute x = 4 in eqn 2

y = 2(4) - 4

y = 8 - 4

y = 4

Thus solution is (4, 4)

5 0

2 years ago

5x + y = -5 I need to graph this pls help

Lisa [10]

Hope this helps
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2 years ago