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2 years ago

When balancing a chemical equation, the number of h atoms in 2 ch4 is eight?

1 answer:

6 0

Yes... that is correct.

CH4 is methane so the coefficent in front of it would double the number of atoms of each element

You might be interested in

How many molecules are in 4.50 moles of H2O?

alisha [4.7K]

C can be the only correct answer - 6.023 x 10^23 is the amount of molecules in a mol of an element. 4.5 x 6.023 x 10^23 can not equal anything but C.

4.5 x 6.023 x 10^23 = 2.71035 x 10^24

8 0

2 years ago

Read 2 more answers

How many particles of Na are there in 1.43g of a molecular compound with a Molar mass of 23g?

Olin [163]

Answer:

3.74 x 10²² particles

Explanation:

Given parameters:

Mass of compound = 1.43g

Molar mass of compound = 23g

Unknown:

Number of particles of sodium = ?

Solution:

To find the number of particles of Na in the compound, we need to obtain the mass of sodium from the total mass given;

Mass of sodium = $\frac{molar mass of Na}{molar mass of compound} x mass of sample$

= $\frac{23}{23} x 1.43g$

= 1.43g

Now find the number of moles of this amount of Na in the sample;

Number of moles = $\frac{mass}{molar mass}$ = $\frac{1.43}{23}$ = 0.062mole

Now;

1 mole of substance = 6.02 x 10²³ particles

0.062 mole of substance = 0.062 x 6.02 x 10²³ particles

= 3.74 x 10²² particles

7 0

2 years ago

PLSSS HELP ME THIS IS FOR SIENCE PLLLLSSSSS

pickupchik [31]

Answer:

Conduction

Explanation:

I took the course

8 0

2 years ago

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Which gas in Earth's atmosphere protects Earth by reflecting untraviolet radiation?

egoroff_w [7]

Answer:

I think it's nitrogen I'm not really sure..

6 0

2 years ago

A 34.57 mL sample of an unknown phosphoric acid solution is titrated with a 0.127 M sodium hydroxide solution. The equivalence p

Bas_tet [7]

<u>Answer:</u> The concentration of unknown phosphoric acid solution is 0.034 M

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_3PO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=3\\M_1=?M\\V_1=34.57mL\\n_2=1\\M_2=0.127M\\V_2=28.2mL$

Putting values in above equation, we get:

$3\times M_1\times 34.57=1\times 0.127\times 28.2\\\\M_1=\frac{1\times 0.127\times 28.2}{3\times 34.57}=0.034M$

Hence, the concentration of unknown phosphoric acid solution is 0.034 M

7 0

2 years ago