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2 years ago

Is Consideringual clay different than sedimentary?

Chemistry

1 answer:

LenaWriter [7]2 years ago

8 0

Answer: No.

Explanation: Clay is filled with minerals that often weather to create shale. Clay is usually found in muddy environments, so it traps.

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A 1.00 cm2 blackbody surface emits 201 watts of radiant power. What is the temperature of the surface? Give to the nearest whole

erastovalidia [21]

Explanation:

Formula for black body radiation is as follows.

$\frac{P}{A} = \sigma \times T^{4} J/m^{2}s$

where, P = power emitted

A = surface area of black body

$\sigma$ = Stephen's constant = $5.6703 \times 10^{-8} watt/m^{2}.K^{-4}$

As area is given as 1.0 $cm^{2}$ . Converting it into meters as follows.

$1.00 cm^{2} \times \frac{(10^{-2})^{2} m^{2}}{1 cm^{2}}$ (as 1 m = 100 cm)

= $1 \times 10^{-4} m^{2}$

It is given that P = 201 watts. Hence,

$\frac{201 watts}{1 \times 10^{-4} m^{2}}$ = $5.6703 \times 10^{-8} watt/m^{2}.K^{-4} \times T^{4}$

$T^{4}$ = $35.45 \times 10^{12}$

T = $(35.45 \times 10^{12})^{1/4}$

= 8862.5 K

Thus, we can conclude that the temperature of the surface is 8862.5 K.

7 0

2 years ago

Draw a lewis structure for XZ2 (X has 6 valence electrons, F has 7 valence electrons)

jarptica [38.1K]

Answer:

yhpcfjfkg original ogigoyy chandan

7 0

2 years ago

Naturally occurring zirconium exists are five isotopes. axe with a mass of 89.905 u(51.45%); Zr with a mass of 90.906 u (11.22%)

Anton [14]

Isotope 1: 89.905 * 51.45 = 4625.61225 / 100 = 46.2561225
Isotope 2: 90.906 * 11.22 = 1019.96532 / 100 = 10.1996532
Isotope 3: 91.905 * 17.15 = 1576.17175 / 100 = 15.7617075
Isotope 4: 93.906 * 17.38 = 1632.08628 / 100 = 16.3208628
Isotope 5: 95.908 * 2.08 = 268.5424 / 100 = 2.685424

46.2561225 + 10.1996532 + 15.7617075 + 16.3208628 + 2.685424 = 91.22377
actual mass Zr = about 91.22

8 0

2 years ago

Natural gas is a mixture of many substances, primarily CH₄, C₂H₆, C3H8, and C4₄H₁₀. assuming that the total pressure of the gase

olchik [2.2K]

Answer:

A. The partial pressure for CH4 = 0.0925atm

B. The partial pressure for C2H6 = 0.925atm

C. The partial pressure for C3H8 = 0.346atm

D. The partial pressure for C4H10 = 0.115atm

Explanation:

Total pressure = 1.48atm

Total mole = 0.4+4+1.5+0.5=6.4

A. Mole fraction of CH4 = 0.4/6.4 = 0.0625

The partial pressure for CH4 = 0.0625 x 1.48 = 0.0925atm

B. Mole fraction of C2H6 = 4/6.4 = 0.625

The partial pressure for C2H6 = 0.625 x 1.48 = 0.925atm

C. Mole fraction of C3H8 = 1.5/6.4 = 0.234

The partial pressure for C3H8 = 0.234 x 1.48 = 0.346atm

D. Mole fraction of C4H10 = 0.5/6.4 = 0.078

The partial pressure for C4H10 = 0.078 x 1.48 = 0.115atm

7 0

2 years ago

I need help with this pls i don’t understand it

FromTheMoon [43]

Answer:

Inner core - A

Outer core - B

Mantle - C

Asthenosphere - F

Lithosphere - E

Crust - D

7 0

7 months ago