1+3x /4= 5/2
1+3x = 5*4/2
1+3x =10
3x =9
x = 3
35.99+5% sales tax=37.79
Hope it helps!
Suppose one of the roots is a the second is 2a. The factors will be:
(x-a) and (x-2a)
thus
(x-a)(x-2a)=x^2+6x+q
x^2-xa-2ax+2a^2=x^2+6x+q
taking corresponding terms we shall have:
-2ax=6x
solving for a we get
-2a=6
thus
a=-3
but
q=2a^2
substituting the value of a we get:
q=2(-3)^2
q=2*9
q=18
Answer:
<h2>12:30 PM</h2>
Step-by-step explanation:
12:00 + :30 (30 minutes) =
12:30
<em>Hope that helps! :)</em>
<em></em>
<em>-Aphrodite</em>
Answer:
A
Step-by-step explanation:
If you look at the Pythagorean theorem, a^2 + b^2 = c^2. Therefore if you square root all of sides, getting rid of the square, you will be left with the length of the sides.
