Answer:
Mass of iodine = 1954.26 g
Explanation:
Given data:
Mass of chlorine react = 546 g
Mass of iodine produced = ?
Solution:
Chemical equation:
2NaI + Cl₂ → 2NaCl + I₂
Number of moles of chlorine:
Number of moles = mass/molar mass
Number of moles = 546 g/71 g/mol
Number of moles = 7.7 mol
Now we will compare the moles of chlorine with iodine.
Cl₂ : I₂
1 : 1
7.7 : 7.7
Mass of iodine:
Mass = number of moles × molar mass
Mass = 7.7 mol × 253.8 g/mol
Mass = 1954.26 g
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Answers:
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At equivalence there is no more HA and no more NaOH, for this particular reaction. So that means we have a beaker of NaA and H2O. The H2O contributes 1 x 10-7 M hydrogen ion and hydroxide ion. But NaA is completely soluble because group 1 ion compounds are always soluble. So NaA breaks apart in water and it just so happens to be in water. So now NaA is broken up. The Na+ doesn't change the pH but the A- does change the pH. Remember that the A anion is from a weak acid. That means it will easily attract a hydrogen ion if one is available. What do you know? The A anion is in a beaker of H+ ions! So the A- will attract H+ and become HA. When this happens, it leaves OH-, creating a basic solution, as shown below.
Answer:
52.99 kPa
Explanation:
Initial volume V1 = 2.7 L
Initial Pressure P1 = 78.5 kPa
Final Volume V2 = 4.0L
Final Pressure P2 = ?
Temperature is constant
The relationship between these quantities is given by the mathematical expression of Boyles law. This is given as;
V1P1 = V2P2
P2 = V1P1 / V2
P2 = 2.7 * 78.5 / 4.0
P2 = 52.99 kPa
