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3 years ago

How many solutions will the following equation have: x squared -49=0

Mathematics

2 answers:

RSB [31]3 years ago

7 0

Xsquere-49=0
Xsquere=49
X=√49 (squere root of 49 is 7)
i.e X=7

nevsk [136]3 years ago

3 0

If u use factoring then x can be 7 or -7

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Brrunno [24]

Remember that an extraneous solution of an equation, is the solution that emerges from solving the equation but is not a valid solution.

Lets solve our equation to find out what is the extraneous solution:
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$x-4=0$ and $x-7=0$
$x=4$ and $x=7$

So, the solutions of our equation are $x=4$ and $x=7$ . Lets replace each solution in our original equation to check if they are valid solutions:
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We can conclude that 7 is a valid solution of the equation.

- For $x=4$
$\sqrt{x-3} =x-5$
$\sqrt{4-3} =4-5$
$\sqrt{1} =1$
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We can conclude that 4 is not a valid solution of the equation; therefore, 4 is a extraneous solution.

We can conclude that the correct answer is: D. the extraneous solution is x = 4

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