Suppose that the functions g and h are defined for all real numbers as follows:

1 answer:

6 0

(h+g)(x) = 3x + 5 + 6x = 9x + 5Answer

(h - g)(x) = 6x - (3x + 5) = 3x- 5 Answer

(h*g)(x) = 6x(3x + 5) = 18x^2 + 30x

(h*g)(2) = 18(4) + 30(2) = 72 + 60 = 132 Answer

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If he = 7x -27 find the value of x

Amiraneli [1.4K]

$\\ \sf\longmapsto 7x-27=1$

$\\ \sf\longmapsto 7x=1+27$

$\\ \sf\longmapsto 7x=28$

$\\ \sf\longmapsto x=\dfrac{28}{7}$

$\\ \sf\longmapsto x=4$

5 0

2 years ago

What number is 0.68 more than 0.44?

natka813 [3]

Answer:

1.12

Step-by-step explanation:

0.68 + 0.44 = 1.12

3 0

2 years ago

How would I go about solving this?

garik1379 [7]

If you draw more of those triangles, there will be 6 that can fit, so find area of 1 triangle and multiply it by 6. Write that number down and then do Pi r squared to find the area of the circle, then do circle area minus triangles area when you get that, divide it by 6. That is the area of the white region so then do Pi R squared again and then subtract the white area from that

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2 years ago

Anyone know the answer?

storchak [24]

Answer:

A. 5-log3 (2)

Step-by-step explanation:

3 0

2 years ago

Write an equation for a parabola in which the set of all points in the plane are equidistant from the focus and line. F(–2, 0);

UNO [17]

The line is called the directrix. Here we have a vertical directrix, so a parabola sideways from usual.

Geometry is best done with squared distances. The squared distance from an arbitrary point (x,y) to the vertical line x=2 is $(x-2)^2.$

We equate that to the squared distance of (x,y) to the focus (-2,0):

$(x-2)^2 = (x - -2)^2 + (y - 0)^2$

$x^2 -4x + 4=x^2 +4x +4 + y^2$

$-8x = y^2$

We could call that done. A more standard form might be

$x =- \dfrac 1 8 \ y^2$

8 0

2 years ago