The measure of the angle ∠PQR is 90 degrees
<h3>How to prove that ∠PQR is 90 degrees?</h3>
The equation of the line PQ is given as:
3x - y - 2 = 0
The coordinates of the QR are given as:
(0, -2) and (6, -4)
Make y the subject in 3x - y - 2 = 0
y = 3x - 2
The slope of the above line is
m1 = 3
Next, we calculate the slope (m2) of points Q and R.
So, we have:
m2 = (y2- y1)/(x2 - x1)
This gives
m2 = (-4 + 2)/(6 - 0)
Evaluate
m2 = -1/3
The slopes of perpendicular lines are opposite reciprocals.
m1 = 3 and m2 = -1/3 are opposite reciprocals.
This means the lines PQ and QR are perpendicular lines.
The angle at the point of perpendicularity is 90 degrees
Hence, the measure of the angle ∠PQR is 90 degrees
Read more about linear equations at:
brainly.com/question/15602982
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Y + 1 = 5(x - 7)
y + 1 = 5x - 35
y = 5x - 36
X²+20=0
x=±√(-80)/2
x=±4i√5/2=2i√5
factorised it is then
(x+2i√5)*(x-2i√5)
Answer:
x = -1.5
Step-by-step explanation:
(0.5x+1.2)–(3.6–4.5x)=(4.8–0.3x)+(10.5x+0.6)
*I would first change any minus signs that are outside of the parenthesis to a plus sign. This is optional, not necessary. *
0.5x + 1.2 + (-3.6) + 4.5x = 4.8–0.3x + 10.5x + 0.6
*Now combine like terms on each side. *
5x + (-2.4) = 10.2x + 5.4
*move all Xs on one side.*
-5.2x = 7.8
*Divide both sides by -5.2 to get X by itself."
x = -1.5