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2 years ago

Find the slope of the line that contains the given pair of points ( 3, -10) and (-8 , -6)

Mathematics

2 answers:

Assoli18 [71]2 years ago

7 0

Answer:

-4/11

Step-by-step explanation:

We can find the slope by using the formula

m = (y2-y1)/ (x2-x1)

= (-6--10)/(-8-3)

= (-6+10)/(-8-3)

= 4/-11

The slope is -4/11

RUDIKE [14]2 years ago

7 0

Happy Valentines Day!

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Step-by-step explanation:

$Slope Formula: \frac{y2 - y1}{x2 - x1}$

$=\frac{-6 - (-10)}{-8 - 3}$

$= \frac{4}{-11}$

It cant be simplified any further.

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Answer:

$\frac{4}{-11}$

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Hope This Helps :)

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Mashcka [7]

13.

(a)

$y=-5x^2+21x-3$

for x = 2:

$y=-5(2)^2+21(2)-3=-20+42-3=19$

for x = 5

$y=-5(5)^2+21(5)-3=-125+105-3=-23$

(b)

The graph is:

(c)

Using the graph:

$\begin{gathered} x=1.8,y=18.6 \\ x=0.548,y=7 \\ x=3.65,y=7 \end{gathered}$ $\begin{gathered} x=1.8 \\ y=-5(1.8)^2+21(1.8)-3=-16.2+37.8-3=18.6 \end{gathered}$ $\begin{gathered} y=7 \\ -5x^2+21x-3=7 \\ -5x^2+21x-10=0 \end{gathered}$

Using the quadratic formula:

$\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x=\frac{-21\pm\sqrt[]{21^2-4(-5)(-10)}}{2(-5)} \\ x=\frac{-21\pm\sqrt[]{241}}{-10} \\ x=0.54758 \\ or \\ x=3.6524 \end{gathered}$