Answer:
T = 92.8 min
Explanation:
Given:
The altitude of the International Space Station t minutes after its perigee (closest point), in kilometers, is given by:
Find:
- How long does the International Space Station take to orbit the earth? Give an exact answer.
Solution:
- Using the the expression given we can extract the angular speed of the International Space Station orbit:
- Where the coefficient of t is angular speed of orbit w = 2*p / 92.8
- We know that the relation between angular speed w and time period T of an orbit is related by:
T = 2*p / w
T = 2*p / (2*p / 92.8)
Hence, T = 92.8 min
The answer of this question is B.
Answer:
It would take time for the capacitor to discharge from to .
It would take time for the capacitor to discharge from to .
Note that , and that.
Explanation:
In an RC circuit, a capacitor is connected directly to a resistor. Let the time constant of this circuit is , and the initial charge of the capacitor be . Then at time , the charge stored in the capacitor would be:
.
<h3>a)</h3>
.
Apply the equation :
.
The goal is to solve for in terms of . Rearrange the equation:
.
Take the natural logarithm of both sides:
.
.
.
<h3>b)</h3>
.
Apply the equation :
.
The goal is to solve for in terms of . Rearrange the equation:
.
Take the natural logarithm of both sides:
.
.
.
Answer:
A.The spring constant for B is one quarter of the spring constant for A.
Explanation:
If spring A oscillates at twice the frequency of spring B, and period is frequency inverted. It means spring B has a period twice of spring A's.
As , and the 2 springs have the same mass
So A.The spring constant for B is one quarter of the spring constant for A. is the correct answer.