Answer:
Solid
Explanation:
As the temperature continues to drop, the matter forms a solid. Due to the solid's low kinetic energy, particles have no "time" to move around, the particles have more "time" to be attracted. Therefore, solids have the strongest intramolecular forces (because they have the strongest attraction).
3H + 3Br = HBr9 Organic chemistry mechanism
Answer:check explanation
Explanation:
(a). HOW THE DISTANCE BETWEEN ELECTRON DONOR AND ACCEPTOR AFFECTS THE RATE OF ELECTRON TRANSFER IN BIOLOGICAL SYSTEM:
Distance between the acceptor and the donor can affect in two ways; short distance and long distance effect.
Short distance causes
electronic orbitals of donor and acceptor directly overlap whereas in LONG DISTANCE reactions this coupling is indirect because of
sequential overlaps of atomic orbitals of the donor, the intervening medium, and the orbitals of the acceptor.
(b). HOW REORGANIZATION ENERGY OF REDOX ACTIVE SPECIE SURROUNDING MEDIUM AFFECTS:
the reorganized energy does not depend on the pre-existing intra molecule electric field. The charge transferred inside the molecule interacts with its aqueous surroundings.
Reorganized energy can be calculated using Poisson-Boltzmann equation.
Answer:
Q was < K. Partial pressure of hydrogen decreased, iodine increased
Explanation:
<em>After iodine was added the Q was [Select] K so the reaction shifted toward the Products [Select] ,The partial pressure of hydrogen [Select], Iodine [Select] |,and hydrogen iodide Decreased</em>
Based on the equilibrium:
H2(g) + I2(g) ⇄ 2HI(g)
K of equilibrium is:
K = [HI]² / [H2] [I2]
<em>Where [] are concentrations at equilibrium</em>
And Q is:
Q = [HI]² / [H2] [I2]
<em>Where [] are actual concentrations of the reactants.</em>
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When the reaction is in equilibrium, K=Q.
But as [I2] is increased, Q decreases and Q was < K
The only concentration that increases is [I2], doing partial pressure of hydrogen decreased, iodine increased
