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2 years ago

_______ currents assist in the transfer of thermal energy from warmer climates to cooler climates.

1 answer:

4 0

It is convection currents that carry thermal energy from warmer places to cooler places. The process operates upon planetary scales, as suggested by the question, but also operates on more local scales such as in your own house. For example, if there is a heater within a single room within your house, convection will drive heat energy to adjacent colder rooms.

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A long ramp made of cast iron is sloped at a constant angle θ = 52.0∘ above the horizontal. Small blocks, each with mass 0.42 kg

dezoksy [38]

Answer:

For cast iron we have

$h = 0.92 m$

For copper

$h = 1.05 m$

For Lead

$h = 1.23 m$

For Zinc

$h = 2.43 m$

Explanation:

As we know that final speed of the block is calculated by work energy theorem

$W_f + W_g = \frac{1}{2}mv^2$

now we have

$-\mu_k mg cos\theta(\frac{h}{sin\theta}) + mgh = \frac{1}{2}mv^2$

now we have

$v^2 = 2gh - 2\mu_k g h cot\theta$

$v = \sqrt{2gh(1 - \mu_k cot\theta)}$

For cast iron we have

$4 = \sqrt{2(9.81)(h)(1 - 0.15cot52)}$

$h = 0.92 m$

For copper

$4 = \sqrt{2(9.81)(h)(1 - 0.29cot52)}$

$h = 1.05 m$

For Lead

$4 = \sqrt{2(9.81)(h)(1 - 0.43cot52)}$

$h = 1.23 m$

For Zinc

$4 = \sqrt{2(9.81)(h)(1 - 0.85cot52)}$

$h = 2.43 m$

4 0

2 years ago

What does keplers second law of planetary monition imply

Gemiola [76]

Kepler's second law of planetary motion describes the speed of a planet traveling in an elliptical orbit around the sun. It states that a line between the sun and the planetsweeps equal areas in equal times. Thus, the speed of theplanet increases as it nears the sun and decreases as it recedes from the sun.

6 0

2 years ago

Read 2 more answers

A man 2 meters tall walks at the rate of 2 meters per second toward a streetlight that's 5 meters above the ground. At what rate

GaryK [48]

Answer:

It changes at a rate of 4/3 meter per second

Explanation:

In the given figure below we have

$\Delta OBD\simeq \Delta ABC\\\\\therefore \frac{5}{X+Y}=\frac{2}{Y}\\\\$

Solving for Y given $X=2m/s$ we get

$\frac{5}{2+Y}=\frac{2}{Y}\\\\5Y=4+2Y\\\\Y=\frac{4}{3}m/s$

8 0

2 years ago

What happens to the current in a circuit if the resistance triples? If the voltage triples?

Sauron [17]

(Example 1 )
If the Voltage that furnishes the current is an ideal (no internal resistance) Voltage source. Then; 

V/R = i 
V/2R = i/2 If external resistance doubles, current reduced to 1/2 of original value 
V/3R = i/3 If external resistance triples, current reduced to 1/3 of original value 

(Example 2) 
But if the Voltage that furnishes the current is a practical [contains an internal resistance (Ri)] Voltage source. Then the current is a function of the Voltage source`s internal resistance, which does not double nor triple, plus the external resistance which is being doubled and tripled. 

V/(R + Ri) = i 
V/(2R + Ri) = greater than i/2 but less than I. 
V/(3R + Ri) = greater than i/3 but less than i/2

7 0

3 years ago

Para que sirve la caida libre

masya89 [10]

Eh? i don’t understand huhu

4 0

2 years ago