Ask question

Ask question

All categories

2 years ago

8

Mr Murray’s distance away (in meters) from his classroom after t seconds can be modeled by the following equation: M(t) = 3.5t +

2. After 3 seconds, how far is Mr Murray away from his classroom?

1 answer:

Vaselesa [24]2 years ago

5 0

Substitute the given value of three into the equation so that it becomes

M= 3.5*3+2

M= 12.5

You might be interested in

Crystal is spinning the spinner at right and claims she has a good chance of having the spinner land on red at least once in thr

-BARSIC- [3]

Wouldn’t the answer be 1/3?

6 0

2 years ago

HELP!! <br> Simplify 12+3(8+x)

cestrela7 [59]

Answer:

24

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Yom-ally has $10,000 property damage liability insurance and a $1,000 deductible on her collision insurance. She drove over a $6

Zarrin [17]

Yom-ally has a 10.000 property damage liability, what means the insurance will pay that amound for propertie, and a 1000 deductible on her collision insurence so:

A) For the bike is a property of the other person so it will be paid with the insurance of $10000 dollars.

B)and it will pay the $600 dollars

C)her car will be paid with the insurance of collision of $1000 dollars

D)and will pay the $900 dollars

3 0

3 months ago

A rose garden Is formed by jolning a rectangle and a semicircle, as shown below. The rectangle Is 23 ft long and 14 ft wide.Find

Ratling [72]

Answer:

Area of the garden:

$\begin{equation*} 398.93\text{ ft}^2 \end{equation*}$

Explanation:

Given the below parameters;

Length of the rectangle(l) = 23 ft

Width of the rectangle(w) = 14 ft

Value of pi = 3.14

Since the width of the rectangle is 14 ft, so the diameter(d) of the semicircle is also 14 ft.

The radius(r) of the semicircle will now be;

$r=\frac{d}{2}=\frac{14}{2}=7\text{ ft}$

Let's now go ahead and determine the area of the semicircle using the below formula;

$A_{sc}=\frac{\pi r^2}{2}=\frac{3.14*\left(7\right)^2}{2}=\frac{3.14*49}{2}=\frac{153.86}{2}=76.93\text{ ft}^2$

Let's also determine the area of the rectangle;

$A_r=l*w=23*14=322\text{ ft}^2$

We can now determine the area of the garden by adding the area of the semicircle and that of the rectangle together;

$\begin{gathered} Area\text{ of the garden = Area of semi circle + Area of rectangle } \\ =76.93+322 \\ =398.93\text{ ft}^2 \end{gathered}$

Therefore, the area of the garden is 398.93 ft^2

8 0

5 months ago

What is the radian measure of an angle of 230º?

asambeis [7]

Correct answer is the last one.

8 0

2 years ago