25.00 gal/min to L/s, Express your answer using four significant figures.

Nitrogen was heated from 17°C to 37°C. The original volume of nitrogen was 8.5 L. Find the new volume in liters assuming P and n

Nata [24]

Answer:

The new volume of the gas is 9.086 liters.

Explanation:

Let suppose that nitrogen has a behavior of ideal gas, the equation of state for ideal gases is:

$P\cdot V = n \cdot R_{u}\cdot T$ (1)

Where:

$P$ - Pressure, measured in atmospheres.

$V$ - Volumen, measured in liters.

$n$ - Molar amount, measured in moles.

$T$ - Temperature, measured in Kelvin.

$R_{u}$ - Ideal gas constant, measured in atmosphere-liters per mole-Kelvin.

If pressure and molar amount of the gas remain constant, then we construct the following relationship:

$\frac{T_{1}}{V_{1}} = \frac{T_{2}}{V_{2}}$ (2)

If we know that $T_{1} = 290.15\,K$ , $P_{1} = 8.5\,L$ and $T_{2} = 310.15\,K$ , then the new volume of the gas is:

$V_{2} = \left(\frac{T_{2}}{T_{1}}\right)\cdot V_{1}$

$V_{2} = \left(\frac{310.15\,K}{290.15\,K} \right)\cdot (8.5\,L)$

$V_{2} = 9.086\,L$

The new volume of the gas is 9.086 liters.

7 0

2 years ago

The electron configuration for Zn2 is [Ar] 3d10 and NOT [Ar] 4s23d8. What experimental evidence has been collected that would al

Anna007 [38]

Answer:

Zn2+ is colourless

Explanation:

We know that transition metal salts are usually coloured due to the possibility of d-d transition.

This d-d transition can only occur when there are vacant d-orbitals. The electronic configuration [Ar] 4s23d8 suggests the presence of vacant d-orbitals and the possibility of the compounds of Zn2+ being coloured.

However, the absence of colours in Zn2+ compounds shows that there is no d-d transition(electronic) spectra observed for Zn2+ because the d orbitals are completely filled. This means that the correct electronic configuration of the ion is [Ar] 3d10.

4 0

2 years ago

sodium-25 was to be used in an experiment but it took 3.0 minutes to get the sodium from the reactor to the laboratory if 5.0 mg

Hoochie [10]

3 half lives later... 5/2 = 2.5mg, then 2.5/2 = 1.25 mg, then 1.25/2 = .625 mg left

7 0

2 years ago

Identify the atoms that are oxidized and reduced, the change in the oxidation state for each, and oxidising and reducing agents

KATRIN_1 [288]

Answer:

Explanation:

a) $Mg + NiCl_2 \rightarrow MgCl_2 + Ni$

Oxidation state of Mg changes to 0 to +2.

Oxidation state of Ni changes to +2 to 0.

Oxidation state of Cl does not change.

So, Mg is oxidized, Ni is reduced.

Mg acts as reducing agent and $NiCl_2$ acts as oxidizing agent.

b) $PCl_3 + Cl_2 \rightarrow PCl_5$

Oxidation state of P changes to +3 to +5.

Oxidation state of Cl changes to 0 to -1.

So,

P is oxidized and Cl is reduced.

$PCl_3$ acts as reducing agent and $Cl_2$ acts as oxidizing agent.

c) $C_2H_4 + 3O_2 \rightarrow 2CO_2 + 2H_2O$

Oxidation state of C changes to -2 to +4.

Oxidation state of O changes to 0 to -2.

Oxidation state of H does not change.

So,

C is oxidized and O is reduced.

$C_2H_4$ acts as reducing agent and $O_2$ acts as oxidizing agent.

d) $Zn + H_2SO_4 \rightarrow ZnSO_4 + H_2$

Oxidation state of Zn changes to 0 to +2.

Oxidation state of H changes to +1 to 0.

Oxidation state of S and O do not change.

So, Zn is oxidized, H is reduced.

Zn acts as reducing agent and $H_2SO_4$ acts as oxidizing agent

e) $K_2S_2O_3 + I_2 \rightarrow K_2S_4_O6 + 2KI$

Oxidation state of S changes to +2 to +2.5.

Oxidation state of I changes to 0 to -1.

Oxidation state of K and O do not change.

So, S is oxidized, I is reduced.

$K_2S_2O_3$ acts as reducing agent and $I_2$ acts as oxidizing agent.

f) $3Cu + 8HNO_3 \rightarrow 3Cu(NO_3)_2 + 4H_2O+2NO$

Oxidation state of Cu changes to 0 to +2.

Oxidation state of N changes to N +5 to +2.

Oxidation state of H and O do not change.

So, Cu is oxidized, N is reduced.

Cu acts as reducing agent and $HNO_3$ acts as oxidizing agent

8 0

2 years ago

Why are some fatty acids called saturated?

Len [333]

Fats (triglycerides) that contain palmitic acid and stearic acid are therefore known as saturated fats. Fats made up of saturated fatty acids are solid at room temperature. ... Because it is polyunsaturated, it is liquid at room temperature.

4 0

2 years ago