<u>Answer:</u>
<u>For 3:</u> The total mass change of the reaction is
<u>For 4:</u> The mass defect is and energy equivalent to this mass is
<u>For 5:</u> The equivalent mass of the reaction is
<u>Explanation:</u>
To calculate the mass change of the reaction for given energy released, we use Einstein's equation:
E = Energy released =
= mass change = ?
c = speed of light =
Putting values in above equation, we get:
Hence, the total mass change of the reaction is
For the given isotopic representation:
Atomic number = Number of protons = 27
Mass number = 60
Number of neutrons = Mass number - Atomic number = 60 - 27 = 33
To calculate the mass defect of the nucleus, we use the equation:
where,
= number of protons = 27
= mass of one proton = 1.00728 amu
= number of neutrons = 33
= mass of one neutron = 1.00867 amu
M = Nuclear mass number = 59.9338 amu
Putting values in above equation, we get:
Converting the value of amu into kilograms, we use the conversion factor:
So,
To calculate the equivalent energy, we use the equation:
E = Energy released = ?
= mass change =
c = speed of light =
Putting values in above equation, we get:
Converting this into kilojoules, we use the conversion factor:
1 kJ = 1000 J
So,
Hence, the mass defect is and energy equivalent to this mass is
For the given chemical reaction:
To calculate the equivalent mass of the reaction for given energy released, we use Einstein's equation:
E = Energy released =
= mass change = ?
c = speed of light =
Putting values in above equation, we get:
Hence, the equivalent mass of the reaction is