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2 years ago

What is the recursive formula for this sequence . 10,14,18,22,26

Mathematics

2 answers:

aniked [119]2 years ago

5 0

Thick it will de 9284

Marrrta [24]2 years ago

4 0

add 4 each time

the nth term is a_n or f(n)

the next term after that is a_{n+1} or f(n+1)

so each term is 4 more than previous

basically

a_{n+1}=4+a_n or

f(n+1)=4+f(n)

same thing

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A city doubles its size every 56 years. If the population is currently 60,000, what will the population be in 112 years?

Anestetic [448]

Answer:

240,000

Step-by-step explanation:

The population is going to get quadrupled. (56 + 56 = 112)

60,000 x 4 = 240,000

Hope this helped! Please mark as brainliest! Thanks!

7 0

2 years ago

A number is divided by 6.then 8 is added Mto the quotient. Next3 is subtracted from the sum.the result is 7. What is the number?

hjlf

(n/6 + 8) - 3 = 7

(n/6 + 8) - 3 + 3 = 7 + 3

n/6 + 8 - 8 = 10 - 8

n/6 = 2

(n/6)(6) = 2(6)

n = 12

6 0

2 years ago

Which is equivalent to (3 + 2i)(5 + i)?

zepelin [54]

(3 + 2i)(5 + i)
15 + 3i + 10i + 2i^2
15 + 13i - 2
13 + 13i

5 0

2 years ago

7. Find the sum or difference.<br> -2(d +1) + (6d +4)

Arturiano [62]

Answer:

Step-by-step explanation:

Sum

-2d + 1 + 6d + 4

Solving like terms

4d + 5

Difference

-2d + 1 - 6d - 4

-8d - 3

4 0

2 years ago

A rectangular tank that is 5324 ft cubed with a square base and open top is to be constructed of sheet steel of a given thicknes

marishachu [46]

Answer:

Side of 22 and height of 11

Step-by-step explanation:

Let s be the side of the square base and h be the height of the tank. Since the tank volume is restricted to 5324 ft cubed we have the following equation:

$V = s^2h = 5324$

$h = 5324 / s^2$

As the thickness is already defined, we can minimize the weight by minimizing the surface area of the tank

Base area with open top $s^2$

Side area 4sh

Total surface area $A = s^2 + 4sh$

We can substitute $h = 5324 / s^2$

$A = s^2 + 4s\frac{5324}{s^2}$

$A = s^2 + 21296/s$

To find the minimum of this function, we can take the first derivative, and set it to 0

$A' = 2s - 21296/s^2 = 0$

$2s = 21296/s^2$

$s^3 = 10648$

$s = \sqrt[3]{10648} = 22$

$h = 5324 / s^2 = 5324 / 22^2 = 11$

4 0

2 years ago