Answer:
5/24
Step-by-step explanation:
hope it works for u good luck
Well it depends on how many tables you are using and if all the sides of the table are equal lengths....you can it will not hurt anything just make sure you right down all of the area length/width that you cover that way you get the amount you need :) remember to hit that thanks button please:)
Answer with explanation:
For, a Matrix A , having eigenvector 'v' has eigenvalue =2
The order of matrix is not given.
It has one eigenvalue it means it is of order , 1×1.
→A=[a]
Determinant [a-k I]=0, where k is eigenvalue of the given matrix.
It is given that,
k=2
For, k=2, the matrix [a-2 I] will become singular,that is
→ Determinant |a-2 I|=0
→I=[1]
→a=2
Let , v be the corresponding eigenvector of the given eigenvalue.
→[a-I] v=0
→[2-1] v=[0]
→[v]=[0]
→v=0
Now, corresponding eigenvector(v), when eigenvalue is 2 =0
We have to find solution of the system
→Ax=v
→[2] x=0
→[2 x] =[0]
→x=0, is one solution of the system.
Answer:
Find something the parts of the equation (which are separated by a sign (+, -, x, or /)) and sort of un-distribute a common number out.
Step-by-step explanation:
Example: 5x + 10
Step One: Find what number they have in common. (5)
Step Two: Divide it from both parts of the equation and put it outside parentheses.
Step Three (result): 5(x+2)