Answer:
60.666667
Step-by-step explanation:
Ok
first of all, for q(x)/p(x)
if the degree of q(x) is less than the degree of p(x),then the horizontal assemtote is 0
then simplify
any factors you factored out is now a hole, remember them
to find the vertical assemtotes of a function, set the SIMPLIFIED denomenator equal to 0 and solve
so
y=(x-5)/(x^2-1)
q(x)<p(x)
horizontal assemtote is y=0
no factors to simplify so no holes
set denomenator to 0 to find vertical assemtote
x^2-1=0
(x-1)(x+1)=0
x-1=0
x=1
x+1=0
x=-1
the horizontal assemtotes are x=1 and -1
Let the leading term of the polynomial, f(x), be axⁿ.
Examine the possibilities.
n a x -> - ∞ x -> +∞
------- ---- ----------- ------------
even a>0 f -> +∞ f -> +∞ Not true
even a<0 f-> - ∞ f-> -∞ True
odd a>0 f-> -∞ f-> +∞ Not true
odd a<0 f-> +∞ f-> -∞ Not true
Answer:
(a) the degree of the polynomial is even, and
(b) the coefficient of the leading term is negative.
You should place 4 red beads and 10 yellow beads into the container. This satisfies both, the ratio and the amount of beads in each container
Answer:
Simplifying
f(r) = 5 + 1.75r
Multiply f * r
fr = 5 + 1.75r
Solving
fr = 5 + 1.75r
Solving for variable 'f'.
Move all terms containing f to the left, all other terms to the right.
Divide each side by 'r'.
f = 5r-1 + 1.75
Simplifying
f = 5r-1 + 1.75
Reorder the terms:
f = 1.75 + 5r-1
Step-by-step explanation:
tada i think