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2 years ago

It takes Julie 75 minutes to read 60 pages.

Mathematics

2 answers:

Montano1993 [528]2 years ago

3 0

A) 5/4
b)75:60 525:350. It will take 525 min. to read the entire book
c) 8 hours and 75 min.

Galina-37 [17]2 years ago

3 0

Answer:

1. 1 1/4

Step-by-step explanation:

2. 437 min, 7 hours and 28 minutes

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2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 in the index form

Dvinal [7]

Answer:

$2^{8}$

Step-by-step explanation:

There are eight 2's so that equals $2^{8}$

Hope this helps! :)

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2 years ago

Which is the solution to 2 x − 6 + 4 = 14 ?

Kaylis [27]

Answer:

x=8

Step-by-step explanation:

2x-6+4=14

Combine like terms

2x-2=14

Add 2

2x=16

Divide

x=8

Checking work)

2(8)-2=14

16-2=14

14=14

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The answer is B! :)

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2 years ago

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What is the area of the figure?

sergij07 [2.7K]

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69.75

Step-by-step explanation:

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A news station would like to conduct an exit poll to determine the likelihood that a highly debated amendment will receive enoug

vladimir1956 [14]

Answer:

The expression is $n = (\frac{1.645*0.5}{0.03})^2$

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a p-value of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

What expression would give the smallest sample size that will result in a margin of error of no more than 3 percentage points?

We have to find n for which M = 0.03.

We have no prior estimate for the proportion, so we use $\pi = 0.5$ . So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.645\sqrt{\frac{0.5*0.5}{n}}$

$0.03\sqrt{n} = 1.645*0.5$

$\sqrt{n} = \frac{1.645*0.5}{0.03}$

$(\sqrt{n})^2 = (\frac{1.645*0.5}{0.03})^2$

$n = (\frac{1.645*0.5}{0.03})^2$

The expression is $n = (\frac{1.645*0.5}{0.03})^2$

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2 years ago