We can use the binomial theorem to find the probability that 0 out of the 15 samples will be defective, given that 20% are defective.
P(0/15) = (15C0) (0.2)^0 (1 - 0.2)^15 = (1)(1)(0.8)^15 = 0.0352
Then the probability that at least 1 is defective is equal to 1 - 0.0352 = 0.9648. This means there is a 96.48% chance that at least 1 of the 15 samples will be found defective. This is probably sufficient, though it depends on her significance level. If the usual 95% is used, then this is enough.
Answer:
attach the graph in orfer for us to answer
Step-by-step explanation:
Answer:
4π(w+1)(w-1)
Step-by-step explanation:
The total surface area of the cylinder
= 2 x area of base circle + area of vertical surface
= 2x pi x radius^2 + 2x pi x radius x height
= 2π(w-1)^2 + 2π(w-1)(w+3)
= 2π[w^2-2w+1 + w^2+2w-3]
= 2π(2w^2-2)
= 4π(w^2 - 1)
= 4π(w+1)(w-1)
We know that this problem is in the ratio of 1:3 1 being adult tickets and 3 being student tickets. If we divide 396 by 4 to get 1 part, then we have the answer.
396/4=99
Answer: 99 adult tickets