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2 years ago

8

How do you do this??

1 answer:

AfilCa [17]2 years ago

5 0

You do

6 over 7 multipled by three.

You multiply 6 and 3= 18

7x1=7

18/7 is the answer

or 2 4/7

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Write an inequality to match this statement: -7 is located to the right of -10. **Hint** You need to use shift and the comma but

vampirchik [111]

Answer:

-7 > -10

Step-by-step explanation:

We just have to compare these two numbers. When you're comparing two negative numbers, the smaller number is the bigger one. Ex. -3 is bigger than -6, so we can say that -3 > -6 (-3 is greater than -6). This means that -7 is larger than -10, which allows you to say that -7 > -10.

3 0

2 years ago

Let the x and y represent the tens digit and ones digit of a two digit number respectively. The sum of the digits of a two-digit

dangina [55]

36
add up to 9
flipped 63-36=27

6 0

2 years ago

(1 point) Find two unit vectors orthogonal to a=⟨4,5,0⟩a=⟨4,5,0⟩ and b=⟨0,1,−3⟩b=⟨0,1,−3⟩ Enter your answer so that the first no

Anni [7]

Answer:

First vector

$V=+ \dfrac{-15i+12j+4k}{\sqrt{385}}$

Second vector

$V=- \dfrac{-15i+12j+4k}{\sqrt{385}}$

Step-by-step explanation:

Given that

Vector a , a= 4 i + 5 j + 0 k

Vector b , b= 0 i + 1 j - 3 k

The orthogonal vector V is given as

V = a x b

V is the cross product of the above two vector which is orthogonal to the vectors a and b.

$V=\begin{vmatrix}i & j & k\\ 4 & 5 & 0\\ 0& 1 &-3 \end{vmatrix}\\V=i(-15-0)-j(-12-0)+k(4-0)\\V=-15i+12j+4k$

The unit vectors

$V=\pm \dfrac{-15i+12j+4k}{\sqrt{15^2+12^2+4^2}}\\\\V=+\dfrac{-15i+12j+4k}{\sqrt{385}}\\V=-\dfrac{-15i+12j+4k}{\sqrt{385}}$

First vector

$V=+ \dfrac{-15i+12j+4k}{\sqrt{385}}$

Second vector

$V=- \dfrac{-15i+12j+4k}{\sqrt{385}}$

5 0

2 years ago

A civil engineer is analyzing the compressive strength of concrete. Compressive strength is normally distributed with σ = 31.62

AysviL [449]

Answer:

A sample size of at least 737 specimens is required.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

Now, find the width M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

In this problem, we have that:

$M = 3, \sigma = 31.62$

So:

$M = z*\frac{\sigma}{\sqrt{n}}$

$3 = 2.575*\frac{31.62}{\sqrt{n}}$

$3\sqrt{n} = 81.4215$

$\sqrt{n} = 27.1405$

$n = 736.60$

A sample size of at least 737 specimens is required.

6 0

2 years ago

PLEASE HELP! WILL MARK BRAINLIEST! (Question below with answers)

Montano1993 [528]

First box, third box, fifth and also sixth =D

8 0

2 years ago