0.22 moles.
28 divided by 124 =0.22
Assuming total mass to be 100 g
Mass of C = 52.93 g
=> Moles of C =
Mass of H = 5.92 g
=> Moles of H=
Mass of N = 41.15 g
=>Moles of N=
Simplest mole ratio of the atoms in the compound:
Empirical formula mass=
Multiple n =
Molecular formula=
Answer:The molecular formula of the oxide of metal be . The balanced equation for the reaction is given by:
Explanation:
Let the molecular formula of the oxide of metal be
Mass of metal product = 1.68 g
Moles of metal X =
1 mol of metal oxide produces 2 moles of metal X.
Then 0.03005 moles of metal X will be produced by:
of metal oxide
Mass of 0.01502 mol of metal oxide = 2.40 g (given)
y = 2.999 ≈ 3
The molecular formula of the oxide of metal be . The balanced equation for the reaction is given by: