Well x^2+10x-3 is a quadratic so we are looking for its lowest point (minimum). If you graph it the answer is (-5, -28) so A. You can do it algebraicallly (x+5)=0. X=-5 and look at -28 for y. Either way you get A as the local minimum/ lowest point of graph.
Answer:
1.3
Step-by-step explanation:
The two points lie on the same vertical line (x=2), so the distance between them is the difference of their y-coordinates:
2.5 - 1.2 = 1.3 . . . distance between the points
Y=mx+b so this means you’ll get the correct answer
Find the LCD = 18
5/6 = 15/18
3/9 = 6/18
15/18 + 6/18 = 21/18 = 7/5 or 1 2/5
Answer:
|x - 1 |> 6,
Step-by-step explanation:
First we find the distance between the two points
-5 to 7
7 - -5 =7+5 = 12
We find 1/2 that distance
12/2 = 6
So we are looking for a greater-than inequality because we are looking for the outsides because we want a less than and a greater than
|x - b |> c,
The center is 6 to that is c
|x - b |> 6,
To find the value of b
Let x = 7
7 -b =6
b=1
|x - 1 |> 6,
We can check by using -5
|-5 - 1 |> 6,
