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2 years ago

How would I set up the equation to find mRQS on this circle?

Mathematics

1 answer:

Leni [432]2 years ago

3 0

MRQS=360-mSR. or mRQS=31x+13...To solve the measure of the minor arc RQS you would use this... 31x+13+(6+18x/2. )=360.

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What is the measure of ∠A, to the nearest degree? 15 POINTS

sasho [114]

Answer:

33 degrees

Step-by-step explanation

I used arcos, ∠A = arccos((a2 + b2 - c2)/2ab)

= 0.5795 rad = 33.203° = 33°12'11"

7 0

2 years ago

Read 2 more answers

mr. smith has a maximum of $50 to spend at a museum. a ticket to the museum costs $7. he can spend p dollars to buy other things

7nadin3 [17]

The inequality that can be used to find the values for p is p + 7 ≤ 50.

Given the information,

Mr. Smith can only spend up to $50 at a museum. The museum admission ticket is $7. He can use his P dollars to purchase other items from the museum.

The total budget is $50.

The cost per ticket is $7

⇒ Total spent ≤ Total Budget

⇒ p + 7 ≤ 50

⇒ p ≤ 43

Therefore, p + 7 ≤ 50 will be the inequality that aids in determining the range of values for p.

To learn more about inequality click here:

brainly.com/question/20383699

#SPJ4

5 0

6 months ago

Please help and show work

Colt1911 [192]

Answer:

24 degrees

Step-by-step explanation:

If the right angle is 90 degrees, and one side of the right angle is 66 degrees, we must subtract 66 from 90. It's 24.

7 0

2 years ago

Y=3/4x+2 how do u graph it

xxMikexx [17]

Answer:

try desmos, type in the equation and it shows you the graph

Step-by-step explanation:

8 0

2 years ago

One gallon of paint covers 400 square feet of surface area. A typical spherical water tower holds 66,840.28 cubic feet of water.

enot [183]

Answer: There will enough to paint the outside of a typical spherical water tower.

Step-by-step explanation:

1. Solve for the radius r from the formula for calculate the volume of a sphere. as following:

$V=\frac{4}{3}r^{3}\pi\\\frac{3V}{4\pi}=r^{3}\\r=\sqrt[3]{\frac{3V}{4\pi}}$

2. Substitute values:

$r=\sqrt[3]{\frac{3(66,840.28ft^{3})}{4\pi}}=25.17ft$

3. Substitute the value of the radius into the equation fo calculate the surface area of a sphere, then you obtain that the surface area of a typical spherical water tower is:

$SA=4r^{2}\pi\\SA=4(25.17ft)^{2} \pi\\SA=7,964.95ft^{2}$

3. If a city has 25 gallons of paint available and one gallon of paint covers 400 square feet of surface area, you must multiply 25 by 400 square feet to know if there will be enough to paint the outside of a typical spherical water tower.

$25*400ft^{2}=10,000ft^{2}$

As you can see, there will enough to paint the outside of a typical spherical water tower.

7 0

2 years ago