The given operation involves just swapping the two rows, so carrying out 
on the matrix gives
![\left[\begin{array}{cc|c}5&5&5\\1&-\dfrac23&5\end{array}\right]\to\left[\begin{array}{cc|c}1&-\dfrac23&5\\5&5&5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D5%265%265%5C%5C1%26-%5Cdfrac23%265%5Cend%7Barray%7D%5Cright%5D%5Cto%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D1%26-%5Cdfrac23%265%5C%5C5%265%265%5Cend%7Barray%7D%5Cright%5D)
4 more than a number is no more than 13
2 answers:
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Step-by-step explanation:
Answer:
The probability that the result is positive is P=0.04475=4.475%.
Step-by-step explanation:
We have the events:
D: disease present
ND: disease not present
P: test positive
F: test false
Then, the information we have is:
P(D)=0.005
P(P | D)=0.99
P(P | ND)=0.04
The total amount of positive test are the sum of the positive when the disease is present and the false positives (positive tests when the disease is not present).
The probability that the result is positive is P=0.04475.