If y varies directly as x, and y =15 as x= -3, find y for the x-value of 6.

Mathematics

1 answer:

VMariaS [17]2 years ago

8 0

Answer:

the answer is -30.

Step-by-step explanation:

for each x-value, you will multiply it by -5 to get your y-value. i say this because if y-15 when x=-3, if you divide the x from y (so 15/-3) you get -5 which is the number in which y varies by. so you will take 6 and multiply it by -5 which gives you -30.

You might be interested in

Alejandro Juarez is paid $829 every two weeks. How much would Alejandro earn in 4 weeks ?

aev [14]

Answer:

$1,658 in 4 weeks

Step-by-step explanation:

Since we are working in intervals of 2, we can just multiply.

829 * 2

1658

Best of luck!

6 0

2 years ago

Read 2 more answers

Which graph best represents the feasibility region for the system shown above? ( pics are in this)

zalisa [80]

Consider the system of inequalities

$\left\{ \begin{array}{l} y\ge 2 \\ x\le 6 \\ y\le 3x+2 \\ y\le -x+10. \end{array}\right.$

1. Plot all lines that are determined by equalities (see attached diagram)

$\left\{ \begin{array}{l} y=2 \text{ (red line)} \\ x= 6 \text{ (blue line)}\\ y=3x+2 \text{ (green line)} \\ y= -x+10 \text{ (orange line)}. \end{array}\right.$

2. Determine which bounded part of the plane you should select:

$y\ge 2$ means that you should take points with y-coordinates greater than or equal to 2 (top part of the coordinate plane that was formed by the red line);
$x\le 6$ means that you should take points with x-coordinates less than or equal to 6 (left part of the coordinate plane that was formed by the blue line);
for $y\le 3x+2$ you can check where the origin is placed. Since $0\le 3\cdot 0+2$ , the origin belongs to the needed part and you have to take the right part of the coordinate plane that was formed by green line.
for $y\le -x+10$ you can check where the origin is placed. Since $0\le -1\cdot 0+10$ , the origin belongs to the needed part and you have to take the bottom part of the coordinate plane that was formed by orange line.