For this case we must find the solution set of the given inequalities:
Inequality 1:
Applying distributive property on the left side of inequality:
Subtracting 3 from both sides of the inequality:
Dividing by 6 on both sides of the inequality:
Thus, the solution is given by all the values of "x" greater than 3.
Inequality 2:
Subtracting 3x from both sides of the inequality:
Subtracting 3 from both sides of the inequality:
Thus, the solution is given by all values of x less than 4.
The solution set is given by the union of the two solutions, that is, all real numbers.
Answer:
All real numbers
The area between the two functions is 0
<h3>How to determine the area?</h3>
The functions are given as:
f₁(x)= 1
f₂(x) = |x - 2|
x ∈ [0, 4]
The area between the functions is
A = ∫[f₂(x) - f₁(x) ] dx
The above integral becomes
A = ∫|x - 2| - 1 dx (0 to 4)
When the above is integrated, we have:
A = [(|x - 2|(x - 2))/2 - x] (0 to 4)
Expand the above integral
A = [(|4 - 2|(4 - 2))/2 - 4] - [(|0 - 2|(0 - 2))/2 - 0]
This gives
A = [2 - 4] - [-2- 0]
Evaluate the expression
A = 0
Hence, the area between the two functions is 0
Read more about areas at:
brainly.com/question/14115342
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Answer:
y=4x would be one
Step-by-step explanation:
I hope its right...
Answer:
Assume that Sk is valid for n=k and prove that Sn is valid for n= k+ 1
Step-by-step explanation:
This is Principle of Mathematical Induction ---PMI
Step 1: Verify that Sn is valid for n =1
Step 2:Assume that Sk is valid for n=k and prove that Sn is valid for n= k+ 1
Answer:
-4
Step-by-step explanation:
Parallel to y= - 1, and passing through (2,-4):