Answer:
No, the reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
Step-by-step explanation:
Consider the provided information.
We need to determine that the reference point selected for the properties of a substance have any effect on thermodynamic analysis.
The answer for this question is No.
The reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
Because in thermodynamic analysis we are deal with the change in the properties.
If we are doing calculation, the reference state chosen is irrelevant as long as we use values in a single consistent array of tables and charts.
Hence, The reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
The point (1, 20) means that the total money spent for purchasing one ticket is $20.
<h3>
Linear equation</h3>
Linear equation is in the form:
y = mx + b
where y, x are variables, m is the slope of the line and b is the y intercept.
Let y represent the total money spent for buying x number of tickets.
The point (1, 20) means that the total money spent for purchasing one ticket is $20.
Find out more on linear equation at: brainly.com/question/14323743
1 week = 7 days....so 1 week and 1/2 day = 7.5 days
2760 / 7.5 = 368 miles per day <==
Answer:
39.275
Step-by-step explanation:
the diameter of the semicircle is 10
A semicircle is half a circle, and a quarter circle is 1/4 of a circle.
Perimeter of a semicircle is ¶d/2
= 3.142 x 10/2 = 3.142 x 5 = 15.71
For 2 semicircles that will be 15.71 x 2 = 31.42
For the quarter circle, perimeter is ¶d/4 = 3.142 x 10/4 = 3.142 x 2.5 = 7.855
Total perimeter = 31.42 + 7.855 = 39.275
Again u just have to meaiuse
