So, We Have A Rate That We Need To Simplify. We Have:
88 students for every 4 classes
So, We Need To Simplify This Rate. In Order To Do This, We Need To Change Is To A Fraction. It Is:
88 students
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4 classes
Now, We Have To Simplify. We Can Do That By Remembering How To Simplify Fractions.
So,
88 ÷ 2 = 44 ÷ 2 = 22 students
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4 ÷ 2 = 2 ÷ 2 = 1
So, The Unit Rate For 88 Students For 4 Classes Is:
22 Students For One Class
Answer:
(7.5 , 5.5)
Step-by-step explanation:
The midpoint is halfway between the two end points:
Its x value is halfway between the two x values
Its y value is halfway between the two y values
To calculate it:
Add both "x" coordinates, divide by 2
Add both "y" coordinates, divide by 2
Answer:
Number 1 is 10 and number 2 is 7
14/2 = 7
7 + 3 = 10
Answer:β=√10 or 3.16 (rounded to 2 decimal places)
Step-by-step explanation:
To find the value of β :
- we will differentiate the y(x) equation twice to get a second order differential equation.
- We compare our second order differential equation with the Second order differential equation specified in the problem to get the value of β
y(x)=c1cosβx+c2sinβx
we use the derivative of a sum rule to differentiate since we have an addition sign in our equation.
Also when differentiating Cosβx and Sinβx we should note that this involves function of a function. so we will differentiate βx in each case and multiply with the differential of c1cosx and c2sinx respectively.
lastly the differential of sinx= cosx and for cosx = -sinx.
Knowing all these we can proceed to solving the problem.
y=c1cosβx+c2sinβx
y'= β×c1×-sinβx+β×c2×cosβx
y'=-c1βsinβx+c2βcosβx
y''=β×-c1β×cosβx + (β×c2β×-sinβx)
y''= -c1β²cosβx -c2β²sinβx
factorize -β²
y''= -β²(c1cosβx +c2sinβx)
y(x)=c1cosβx+c2sinβx
therefore y'' = -β²y
y''+β²y=0
now we compare this with the second order D.E provided in the question
y''+10y=0
this means that β²y=10y
β²=10
B=√10 or 3.16(2 d.p)
