5) a. The equation that describes the forces which act in the x-direction: <span> Fx = 200 * cos 30 </span> <span> b. The equation which describes the forces which act in the y-direction: </span> <span> Fy = 200 * sin 30 </span>
<span>c. The x and y components of the force of tension: </span> <span> Tx = Fx = 200 * cos 30 </span> <span> Ty = Fy = 200 * sin 30 </span>
d.<span>Since desk does not budge, </span><span>frictional force = Fx = 200 * cos 30 </span>
<span> Normal force </span><span>= 50 * g - Fy = 50 g - 200 * sin 30 </span>____________________________________________________________ 6)<span> Let F_net = 0</span> a. The equation that describes the forces which act in the x-direction: (200N)cos(30) - F_s = 0
b. The equation that describes the forces which act in the y-direction: F_N - (200N)sin(30) - mg = 0
c. The values of friction and normal forces will be: Friction force= (200N)cos(30),
The Normal force is not 490N in either case... Case 1 (pulling up) F_N = mg - (200N)sin(30) = 50g - 100N = 390N
