Answer:
The answer to your question is 245 grams
Explanation:
Data
Volume 6.5 L
Molarity = 0.34
mass of CaCl₂ = ?
Process
1.- Calculate the molar mass of CaCl₂
molar mass = (1 x 40) + (2 x 35.5)
= 40 + 71
= 111 g
2.- Convert the grams to moles
111 g of CaCl₂ -------------- 1 mol
x ---------------0.34 mol
x = (0.34 x 111) / 1
x = 37.74 g
3.- Calculate the total mass
37.74 g ------------------ 1 L
x ------------------ 6.5 L
x = (6.5 x 37.74) / 1
x = 245.31
Mass number = protons + neutrons
mass number = 5 + 7
mass number = 12
Diffusion is the process of a substance spreading out to evenly fill its container or environment. Rate of diffusion of a gas is inversely proportional to the molar mass of the gas.
Lighter(lower) the molar mass of the gas , faster will be its rate of diffusion and heavier (higher) the molar mass of the gas , slower will be its rate of diffusion.
We have to arrange the given gases from slowest rate of diffusion to fastest rate of diffusion that means we need to arrange gases from higher molar mass to lower molar mass.
Molar mass of given gases are :
Cl = 35.5 g/mol
Xe = 131.29 g/mol
He = 4.00 g/mol
N = 14.00 g/mol
So correct order for slowest rate of diffusion (highest molar mass) to fastest rate of diffusion (lowest molar mass) is :
Xe , Cl , N , He
Xe having the highest molar mass will have the slowest rate of diffusion and He with lowest molar mass will have the fastest rate of diffusion, so option 'c' is correct.
Note : Slowest rate of diffusion = High Molar Mass
Fastest rate of diffusion = Low Molar Mass
Answer:
In order to rinse the system of exhaled CO2 and meet the inspiratory flow rate requirements of infants placed on B-CPAP, the flow rate of humidified gas should be set at:
A. 16 to 20 L/minute
B. 6 to10 L/minute
C. at least 15 L/minute
D. 11 to 15 L/minute
B. 6 to10 L/minute
Explanation:
Bubble CPAP is a non-invasive, external ventilation technique used for newborn babies with infant respiratory distress syndrome (IRDS). Continuous positive airway pressure (CPAP) is given to a spontaneously breathing newborn baby to preserve lung volumes during expiration
Answer:
Explanation:
2N₂O(g) → 2N₂(g) + O₂(g)
molecular weight of N₂O = 44
∆Hº = –166.7 kJ/mol
44 g of N₂O decomposes to give 166.7 kJ of heat
2.25 g of N₂O decomposes to give 166.7 x 2.25 / 44 kJ of heat
= 8.51 kJ of heat .