All categories

2 years ago

The area of a rectangel is 36 square centimeters, and it's length is 9 centimeters?

Mathematics

2 answers:

Sindrei [870]2 years ago

6 0

I think the answeris 4 because 4times 9 gives u 36

Anon25 [30]2 years ago

6 0

If the length is 9 centimeters then the width should be 4 centimeters. 9cm×4cm=36cm. 36cm is Area. 9cm is your length. Then 4cm must be width.

You might be interested in

The sum of two consecutive integers is 41. Find the integers

BigorU [14]

20 and 21 is your answer

20 + 21 = 41

hope this helps

3 0

2 years ago

If you know that a < b, and both a and b are positive numbers, then what must be true about the relationship between the oppo

nlexa [21]

What ever number A is, it is going to be less than whatever number B is.

8 0

2 years ago

Read 2 more answers

Find the absolute extrema for f(x,y)=4-x^2-y^4+1/2y^2 over the closed disk D:x^2+y^2 is less than or equal to 1

algol [13]

Find the critical points of $f(x,y)$ :

$\dfrac{\partial f}{\partial x}=-2x=0\implies x=0$

$\dfrac{\partial f}{\partial y}=y-4y^3=y(1-4y^2)=0\implies y=0\text{ or }y=\pm\dfrac12$

All three points lie within $D$ , and $f$ takes on values of

$\begin{cases}f(0,0)=4\\f\left(0,-\frac12\right)=\frac{65}{16}\\f\left(0,\frac12\right)=\frac{65}{16}\end{cases}$

Now check for extrema on the boundary of $D$ . Convert to polar coordinates:

$f(x,y)=f(\cos t,\sin t)=g(t)=4-\cos^2-\sin^4t+\dfrac12\sin^2t=3+\dfrac32\sin^2t-\sin^4t$

Find the critical points of $g(t)$ :

$\dfrac{\mathrm dg}{\mathrm dt}=3\sin t\cos t-4\sin^3t\cos t=\sin t\cos t(3-4\sin^2t)=0$

$\implies\sin t=0\text{ or }\cos t=0\text{ or }\sin t=\pm\dfrac{\sqrt3}2$

$\implies t=n\pi\text{ or }t=\dfrac{(2n+1)\pi}2\text{ or }\pm\dfrac\pi3+2n\pi$

where $n$ is any integer. There are some redundant critical points, so we'll just consider $0\le t< 2\pi$ , which gives

$t=0\text{ or }t=\dfrac\pi3\text{ or }t=\dfrac\pi2\text{ or }t=\pi\text{ or }t=\dfrac{3\pi}2\text{ or }t=\dfrac{5\pi}3$

which gives values of

$\begin{cases}g(0)=3\\g\left(\frac\pi3\right)=\frac{57}{16}\\g\left(\frac\pi2\right)=\frac72\\g(\pi)=3\\g\left(\frac{3\pi}2\right)=\frac72\\g\left(\frac{5\pi}3\right)=\frac{57}{16}\end{cases}$

So altogether, $f(x,y)$ has an absolute maximum of 65/16 at the points (0, -1/2) and (0, 1/2), and an absolute minimum of 3 at (-1, 0).

5 0

2 years ago

Fabio has run five eighths of the race. What fraction of the race remains?

Pavel [41]

Answer:

$\frac{3}{8}$

Step-by-step explanation:

<h2><u>Fractions </u></h2>

since $\frac{5}{8}$ has been completed

the remaining would be :

$\frac{8}{8} -\frac{5}{8}$

since <em>denominators are the same </em>

= $\frac{8 - 5}{8} \\\\$

= $\frac{3}{8}$

<u>the fraction of the race that is remaining is 3/8</u>

7 0

2 years ago

Read 2 more answers

URGENTLY ANSWER, RIGHT TRIANGLE TRIGNOMETRY

Otrada [13]

So for this you will be doing proportions. Your equation will look like this: $\frac{5}{DE} =\frac{DE}{20}$

Firstly, cross multiply: $DE^2=100$

Next, square root both sides of the equation, and your answer should be $DE=10$

3 0

2 years ago