The width of the walkway around the pool will be 2 feet.
<h3>What is the area of the rectangle?</h3>
Let L be the length and W be the width of the rectangle.
Then the area of the rectangle will be
Area of the rectangle = L × W square units
Nicole is building a walkway with a width of x feet to go around a swimming pool that measures 11 feet by 7 feet.
Let a be the width of the walkway.
The area of the pool will be
If the total area of the pool and the walkway will be 165 square feet.
Area of pool = (11 + 2a) x (7 + 2a)
165 = 4a² + 36a + 77
4a² + 36a - 88 = 0
a² + 9a - 22 = 0
a² + 11a - 2a - 22 = 0
(a + 11)(a - 2) = 0
a = -11, 2
The width of the walkway around the pool will be 2 feet.
More about the area of the rectangle link is given below.
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Answer:
There could be many answers: 2/12, 3/18, 4/24...
Step-by-step explanation:
You never really gave options but all you do is just take 1/6 and multiply the top and bottom by a certain number to get what you're looking for, for example 1/6 times 2, both on the top and bottom will get you 2/12 because 1 times 2 is 2 and, 6 time 2 is 12. :)
Answer:
I'm going to assume you meant 1.5 pounds and not 15 pounds each month.
Step-by-step explanation:
1.5*6=9
C
Answer:
B) Maximums: (0, 1), (2π, 1);
Minimum: (π, -3)
Answer:
X= 25, the second one is 22, the third one is 19
y=20, the second one is 17, the thirst one is 12
The terms in patten y is 5 less than the terms in pattern x
Step-by-step explanation: