If planet A is three times as far from planet C, then the period of its orbit will be __ times as long

1 answer:

6 0

I may be wrong, but I think you're trying to say that Planet-A is
3 times as far from the sun as Planet-C is.

If that's the real question, then the answer is that the period of Orbit-A
is about 5.2 times as long as the period of Orbit-C .

Orbital period ≈ (proportional to) (the orbital distance) ^ 3/2 power.

This was empirically demonstrated about 350 years ago by Johannes
and his brilliant Kepple, and derived about 100 years later by Newton
from his formula for the forces of gravity.

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If the emf produced in a wire is 0.88 volts and the wire moves perpendicular to a magnetic field of strength 0.075 newtons/amper

Elza [17]

Emf = d (phi-B) / dt
B dA/dt, where dA/dt is the area swept out by the wire per unit time. 
0.88 V = (0.075 N/(A m)) (L)(4.20 m/s), so 
L = (0.88 J/C) / [ (0.075 N s/C m)(4.2 m/s) ] = about 3 meters

6 0

2 years ago

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A charged object is suspended motionless in the air by the gravitational force pulling it down and an electric force pushing it

Savatey [412]

The charge of the object must be $1.11 \times e^{-5} \text { coulomb }$

Answer: Option C

Explanation:

Suppose an electric charge can be represented by the symbol Q. This electric charge generates an electric field; Because Q is the source of the electric field, we call this as source charge. The electric field strength of the source charge can be measured with any other charge anywhere in the area. The test charges used to test the field strength.

Its quantity indicated by the symbol q. In the electric field, q exerts an electric, either attractive or repulsive force. As usual, this force is indicated by the symbol F. The electric field’s magnitude is simply defined as the force per charge (q) on Q.

$Electric field, E=\frac{\text { Force }(F)}{q}$