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2 years ago

Can you plz find the area of the parallelogram??

Mathematics

2 answers:

Wittaler [7]2 years ago

7 0

Is 50.5 the area the parallelogram

levacccp [35]2 years ago

6 0

13.5·18=243
Base* Hight= Answer

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HELP ME PLEASE WITH 1,2 AND 3 PLEASE DON'T TAKE LONG TO RESPOND !!

soldi70 [24.7K]

Answer:

1. -19x

3. 23 - 8x

5. -18x + 2y

Step-by-step explanation:

first: 3x - x = 2x

2x - 22x = -20x

-20x + x = -19x

second one:

8 - (-15) = 23

12x - 20x = -8 x

23 - 8x

third:

-10x - 8x = -18x

3y - y = 2y

-18x + 2y

6 0

2 years ago

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The first eight quizzes in this class had average scores of 8,9,9,8,8,9,8,7. This gives a sample mean of 8.25 and a sample stand

alexira [117]

Answer:

Test statistic

$t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }$

t = 1.076

Step-by-step explanation:

Step(i):-

Given Mean of the Population (μ) = 8.0

Mean of the sample (x⁻) = 8.25

Given data

8,9,9,8,8,9,8,7

Given sample size n= 8

Given sample standard deviation(S) = 0.661

Step(ii):-

Null hypothesis : H: (μ) = 8.0

Alternative Hypothesis :H:(μ) > 8.0

Degrees of freedom = n-1 = 8-1=7

Test statistic

$t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }$

$t = \frac{8.25 -8.0}{\frac{0.661}{\sqrt{8} } }$

t = 1.076

Critical value

t₍₇,₀.₀₅₎ = 2.3646

The calculated value t = 1.076 < 2.3646 at 0.05 level of significance

Null hypothesis is accepted

Test the hypothesis that the true mean quiz score is 8.0 against the alternative that it is not greater than 8.0

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2 years ago

Find several points that are on the graph of the function y = x^2 + 1. Plot the points in a coordinate plane.

beks73 [17]

Answer:

Below.

Step-by-step explanation:

Plot following points.

Calculate the point by plugging in values of x into x^2 + 1

for example When x = 0, y = 0^1 + 1 = 1.

So plot plot (0, 1),

Make a table of points to plot:

x -3 -2 -1 0 1 2 3

y 10 5 2 1 2 5 10

When you plot the points you'll see the graph is U shaped.

The function is of second degree (as it contains x^2) so it wont be linear.

8 0

2 years ago

There are 28 students in a class. 13 of the students are boys. Two students from the class are chosen at random. a) If the first

Luba_88 [7]

Answer:

Step-by-step explanation:

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1 year ago

Peter has 3200 yards of fencing to enclose a rectangular area. Find the dimensions of the rectangle that maximize the enclosed a

salantis [7]

Answer:

$A = 640000\,yd^{2}$

Step-by-step explanation:

Expression for the rectangular area and perimeter are, respectively:

$A (x,y) = x\cdot y$

$3200\,yd = 2\cdot (x+y)$

After some algebraic manipulation, area expression can be reduce to an one-variable form:

$y = 1600 -x$

$A (x) = x\cdot (1600-x)$

The first derivative of the previous equation is:

$\frac{dA}{dx}= 1600-2\cdot x$

Let the expression be equalized to zero:

$1600-2\cdot x=0$

$x = 800$

The second derivative is:

$\frac{d^{2}A}{dx^{2}} = -2$

According to the Second Derivative Test, the critical value found in previous steps is a maximum. Then:

$y = 800$

The maximum area is:

$A = (800\,yd)\cdot (800\,yd)$

$A = 640000\,yd^{2}$

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2 years ago

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