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BaLLatris [955]

2 years ago

15

There was d dollars in the savings account when mr Duane withdrew $45 from the account. Then me Duane deposited and additional $

65 into the account

1 answer:

Basile [38]2 years ago

6 0

What are you asking ???
Write it in an equation ???
d+65-45=Final Balance
D+20=Final Balance
Not sure if this is what you're looking for !

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11<br> Which improper fraction is equivalent to 5 ?<br> 40

Nataly_w [17]

Answer:

211/40, B

Step-by-step explanation:

Make it an improper fraction:

5 x 40 = 200, 200 + 11 = 211

211/40, B

3 0

2 years ago

Need answer will give brainlist if correct!

tensa zangetsu [6.8K]

Answer:

a. 4/52

b. 8/52

c. 13/52

d.1/52

8 0

2 years ago

Read 2 more answers

Which of the following cannot be used to state a postulate?

liubo4ka [24]

Among the four choices, theorems is the best possible answer. Postulate, by definition, is a statement that is assumed to be true without proof while theorems are true statements that can be proven. Both of these types of statements are used to justify geometrical equations, illustrations and statements.

6 0

2 years ago

Find the sum of a finite geometric sequence from n = 1 to n = 7, using the expression −4(6)n − 1.

Verizon [17]

Answer:

<h2>-223,948</h2>

Step-by-step explanation:

The formula of a sum of terms of a gometric sequence:

$S_n=a_1\cdot\dfrac{1-r^n}{1-r}$

a₁ - first term

r - common ratio

We have

$a_n=-4(6)^{n-1}$

Calculate a₁. Put n = 1:

$a_1=-4(6)^{1-1}=-4(6)^0=-4(1)=-4$

Calculate the common ratio:

$r=\dfrac{a_{n+1}}{a_n}\\\\a_{n+1}=-4(6)^{n+1-1}=-4(6)^n\\\\r=\dfrac{-4(6)^n}{-4(6)^{n-1}}=6^n:6^{n-1}\\\\\text{use}\ a^n:a^m=a^{n-m}\\\\r=6^{n-(n-1)}=6^{n-n+1}=6^1=6$

$\text{Substitute}\ a_1=-4,\ n=7,\ r=6:\\\\S_7=-4\cdot\dfrac{1-6^7}{1-6}=-4\cdot\dfrac{1-279936}{-5}=-4\cdot\dfrac{-279935}{-5}=(-4)(55987)\\\\S_7=-223948$

7 0

3 years ago

Vikki [24]

Answer:

(B)15,36,39

Step-by-step explanation:

To determine which of the line segments could create a Right Triangle, we check if it satisfies the Pythagoras Theorem, taking the longest part to be the Hypotenuse in all cases.

By Pythagoras Theorem: $Hypotenuse^2=Opposite^2+Adjacent^2$

In 15,30,35

$35^2\neq 15^2+30^2\\1225\neq 1125$

In 15,36,39

$39^2=36^2+15^2\\1521=1521$

In 15, 20, 29

$29^2\neq 15^2+20^2\\841\neq 625$

In 5,15,30

$30^2\neq 15^2+5^2\\900\neq 250$

We can see that only 15,36,39 satisfies the required condition and thus it could be used to create a right triangle.

4 0

2 years ago